Class 9 Chapter 6 Lines and Angles Questions with Detailed Solutions

Chapter 6: Lines and Angles in Geometry. Below are 30 questions with solutions based on this chapter:


Section 1: Basic Concepts

  1. Define an angle.
    Answer:
    An angle is the figure formed by two rays (called the sides of the angle) meeting at a common endpoint (called the vertex).
  2. What are adjacent angles?
    Answer:
    Adjacent angles are two angles that share a common vertex and a common arm but do not overlap.
  3. What is the difference between a straight angle and a reflex angle?
    Answer:
    • A straight angle is an angle that measures exactly 180°.
    • A reflex angle is an angle that is greater than 180° but less than 360°.
  4. If two angles are complementary, and one angle is 30°, what is the other angle?
    Answer:
    Complementary angles sum to 90°.
    The other angle is:90°−30°=60°90° – 30° = 60°90°−30°=60°
  5. What is the sum of the interior angles of a quadrilateral?
    Answer:
    The sum of the interior angles of a quadrilateral is always 360°.

Section 2: Types of Angles

  1. Define a right angle.
    Answer:
    A right angle is an angle that measures exactly 90°.
  2. What is the measure of an obtuse angle?
    Answer:
    An obtuse angle is one that measures greater than 90° but less than 180°.
  3. If two angles are supplementary and one angle is 110°, what is the measure of the other angle?
    Answer:
    Supplementary angles sum to 180°.
    Therefore, the other angle is:180°−110°=70°180° – 110° = 70°180°−110°=70°
  4. What is the relationship between the angles in a linear pair?
    Answer:
    A linear pair consists of two adjacent angles that form a straight line, and their sum is always 180°.
  5. What are vertically opposite angles?
    Answer:
    Vertically opposite angles are the angles formed when two lines intersect. They are always equal in measure.

Section 3: Parallel Lines and Transversal

  1. What is a transversal line?
    Answer:
    A transversal is a line that intersects two or more lines at different points.
  2. State the Corresponding Angles Postulate.
    Answer:
    The Corresponding Angles Postulate states that if two parallel lines are cut by a transversal, then each pair of corresponding angles is equal.
  3. State the Alternate Interior Angles Theorem.
    Answer:
    The Alternate Interior Angles Theorem states that if two parallel lines are cut by a transversal, then each pair of alternate interior angles is equal.
  4. If two parallel lines are cut by a transversal, what is the sum of the interior angles on the same side of the transversal?
    Answer:
    The interior angles on the same side of the transversal are supplementary, i.e., their sum is 180°.
  5. What happens to the angles if a transversal cuts two lines that are not parallel?
    Answer:
    If a transversal cuts two lines that are not parallel, the angles formed by the transversal may not have any special relationship like the corresponding angles or alternate interior angles.

Section 4: Angles and their Properties

  1. Find the value of xxx if two angles are complementary and one angle is 2x2x2x, and the other angle is 3x3x3x.
    Answer:
    Since the angles are complementary, their sum is 90°.2x+3x=90°⇒5x=90°⇒x=18°2x + 3x = 90° \Rightarrow 5x = 90° \Rightarrow x = 18°2x+3x=90°⇒5x=90°⇒x=18°
  2. What is the measure of the exterior angle of a triangle?
    Answer:
    The exterior angle of a triangle is equal to the sum of the two non-adjacent interior angles.
  3. If the measure of two supplementary angles is 3x+20°3x + 20°3x+20° and 2x+40°2x + 40°2x+40°, find the value of xxx.
    Answer:
    Since the angles are supplementary, their sum is 180°.(3x+20°)+(2x+40°)=180°⇒5x+60°=180°⇒5x=120°⇒x=24°(3x + 20°) + (2x + 40°) = 180° \Rightarrow 5x + 60° = 180° \Rightarrow 5x = 120° \Rightarrow x = 24°(3x+20°)+(2x+40°)=180°⇒5x+60°=180°⇒5x=120°⇒x=24°
  4. In a triangle, if two angles measure 60° and 40°, what is the measure of the third angle?
    Answer:
    The sum of the angles in a triangle is always 180°.
    The third angle is:180°−60°−40°=80°180° – 60° – 40° = 80°180°−60°−40°=80°
  5. If the measure of an angle is 3 times the measure of its complement, find the angle.
    Answer:
    Let the angle be xxx, and its complement is 90°−x90° – x90°−x.
    According to the problem:x=3(90°−x)x = 3(90° – x)x=3(90°−x) x=270°−3x⇒4x=270°⇒x=67.5°x = 270° – 3x \Rightarrow 4x = 270° \Rightarrow x = 67.5°x=270°−3x⇒4x=270°⇒x=67.5°

Section 5: Applications of Angle Properties

  1. What is the angle between the hour hand and minute hand of a clock at 3:00?
    Answer:
    At 3:00, the hour hand is at 3, and the minute hand is at 12. The angle between them is 90°.
  2. Find the exterior angle of a regular hexagon.
    Answer:
    The sum of the exterior angles of any polygon is 360°.
    For a regular hexagon, each exterior angle is:360°6=60°\frac{360°}{6} = 60°6360°​=60°
  3. How do you calculate the angle between two parallel lines cut by a transversal?
    Answer:
    You can use the properties of corresponding angles, alternate interior angles, or consecutive interior angles depending on the question. For parallel lines cut by a transversal, angles formed will have these relationships.
  4. If two lines are parallel, what is the relationship between their slopes?
    Answer:
    If two lines are parallel, then their slopes are equal.
  5. Find the value of xxx if the interior angles of a quadrilateral are (x+10)°(x+10)°(x+10)°, (2x−20)°(2x-20)°(2x−20)°, (3x+10)°(3x+10)°(3x+10)°, and (x+20)°(x+20)°(x+20)°.
    Answer:
    The sum of the interior angles of a quadrilateral is 360°.(x+10)+(2x−20)+(3x+10)+(x+20)=360°(x+10) + (2x-20) + (3x+10) + (x+20) = 360°(x+10)+(2x−20)+(3x+10)+(x+20)=360°Simplifying:7x+20=360°⇒7x=340°⇒x=340°7≈48.57°7x + 20 = 360° \Rightarrow 7x = 340° \Rightarrow x = \frac{340°}{7} \approx 48.57°7x+20=360°⇒7x=340°⇒x=7340°​≈48.57°

Section 6: Miscellaneous Questions

  1. What is the relationship between the interior and exterior angles of a polygon?
    Answer:
    The interior and exterior angles of a polygon are supplementary, meaning their sum is always 180°.
  2. How do you find the measure of an interior angle of a regular polygon?
    Answer:
    The measure of an interior angle of a regular polygon with nnn sides is given by:(n−2)×180°n\frac{(n – 2) \times 180°}{n}n(n−2)×180°​
  3. What is the measure of the interior angle of a regular pentagon?
    Answer:
    The number of sides in a pentagon is 5. The measure of an interior angle is:(5−2)×180°5=3×180°5=108°\frac{(5 – 2) \times 180°}{5} = \frac{3 \times 180°}{5} = 108°5(5−2)×180°​=53×180°​=108°
  4. If two angles are supplementary, and one is x+30°x + 30°x+30° and the other is 2x−10°2x – 10°2x−10°, find the value of xxx.
    Answer:
    Since the angles are supplementary:(x+30°)+(2x−10°)=180°⇒3x+20°=180°⇒3x=160°⇒x=160°3≈53.33°(x + 30°) + (2x – 10°) = 180° \Rightarrow 3x + 20° = 180° \Rightarrow 3x = 160° \Rightarrow x = \frac{160°}{3} \approx 53.33°(x+30°)+(2x−10°)=180°⇒3x+20°=180°⇒3x=160°⇒x=3160°​≈53.33°
  5. Find the value of xxx if the two angles are supplementary and one angle is 4x4x4x and the other is 3x+40°3x + 40°3x+40°.
    Answer:
    Supplementary angles sum to 180°.4x+(3x+40°)=180°⇒7x+40°=180°⇒7x=140°⇒x=20°4x + (3x + 40°) = 180° \Rightarrow 7x + 40° = 180° \Rightarrow 7x = 140° \Rightarrow x = 20°4x+(3x+40°)=180°⇒7x+40°=180°⇒7x=140°⇒x=20°

Here are 20 additional questions based on Chapter 6: Lines and Angles with their answers:


Section 1: Basic Angle Properties

  1. What is the measure of each interior angle of a regular octagon?
    Answer:
    The sum of the interior angles of an octagon (8-sided polygon) is:(8−2)×180°=1080°(8 – 2) \times 180° = 1080°(8−2)×180°=1080°Each interior angle is:1080°8=135°\frac{1080°}{8} = 135°81080°​=135°
  2. If two angles are supplementary and one angle is 4 times the other, find the angles.
    Answer:
    Let the smaller angle be xxx, and the larger angle is 4x4x4x.
    Since they are supplementary:x+4x=180°⇒5x=180°⇒x=36°x + 4x = 180° \Rightarrow 5x = 180° \Rightarrow x = 36°x+4x=180°⇒5x=180°⇒x=36°Therefore, the smaller angle is 36°, and the larger angle is 4×36°=144°4 \times 36° = 144°4×36°=144°.
  3. If two angles are complementary, and one angle is twice the other, find the angles.
    Answer:
    Let the smaller angle be xxx, and the larger angle is 2x2x2x.
    Since they are complementary:x+2x=90°⇒3x=90°⇒x=30°x + 2x = 90° \Rightarrow 3x = 90° \Rightarrow x = 30°x+2x=90°⇒3x=90°⇒x=30°Therefore, the smaller angle is 30°, and the larger angle is 2×30°=60°2 \times 30° = 60°2×30°=60°.
  4. What is the measure of an exterior angle of a regular dodecagon?
    Answer:
    The sum of the exterior angles of any polygon is 360°.
    For a regular dodecagon (12-sided polygon), each exterior angle is:360°12=30°\frac{360°}{12} = 30°12360°​=30°
  5. What is the sum of the interior angles of a hexagon?
    Answer:
    The sum of the interior angles of a hexagon is:(6−2)×180°=720°(6 – 2) \times 180° = 720°(6−2)×180°=720°

Section 2: Parallel Lines and Transversals

  1. Two parallel lines are cut by a transversal. If one of the corresponding angles measures 50°, what is the measure of the corresponding angle on the other line?
    Answer:
    Corresponding angles are equal when two parallel lines are cut by a transversal.
    Therefore, the corresponding angle on the other line is also 50°.
  2. Find the value of xxx if two parallel lines are cut by a transversal, and one alternate interior angle is 3x+10°3x + 10°3x+10° and the other is 4x−20°4x – 20°4x−20°.
    Answer:
    Since alternate interior angles are equal:3x+10°=4x−20°3x + 10° = 4x – 20°3x+10°=4x−20°Solving for xxx:3x−4x=−20°−10°⇒−x=−30°⇒x=30°3x – 4x = -20° – 10° \Rightarrow -x = -30° \Rightarrow x = 30°3x−4x=−20°−10°⇒−x=−30°⇒x=30°
  3. If two lines are parallel, what is the relationship between the consecutive interior angles formed by a transversal?
    Answer:
    Consecutive interior angles are supplementary, meaning their sum is 180°.
  4. Two lines are parallel and are cut by a transversal. If one of the interior angles is 2x+30°2x + 30°2x+30° and the corresponding exterior angle is 3x−10°3x – 10°3x−10°, find xxx.
    Answer:
    Since the interior angle and the exterior angle form a linear pair, their sum is 180°.(2x+30°)+(3x−10°)=180°(2x + 30°) + (3x – 10°) = 180°(2x+30°)+(3x−10°)=180°Simplifying:5x+20°=180°⇒5x=160°⇒x=32°5x + 20° = 180° \Rightarrow 5x = 160° \Rightarrow x = 32°5x+20°=180°⇒5x=160°⇒x=32°
  5. If two parallel lines are cut by a transversal, and the measure of one of the alternate interior angles is 70°, what is the measure of the other alternate interior angle?
    Answer:
    Alternate interior angles are equal when two parallel lines are cut by a transversal.
    Therefore, the other alternate interior angle is also 70°.

Section 3: Linear Pair and Vertically Opposite Angles

  1. If two angles form a linear pair and one angle is 85°, what is the measure of the other angle?
    Answer:
    The angles in a linear pair are supplementary, meaning their sum is 180°.
    Therefore, the other angle is:

180°−85°=95°180° – 85° = 95°180°−85°=95°

  1. What is the measure of the vertically opposite angle if one of the angles formed by two intersecting lines is 120°?
    Answer:
    Vertically opposite angles are equal.
    Therefore, the vertically opposite angle is also 120°.
  2. If two lines intersect at a point, what is the sum of the adjacent angles formed?
    Answer:
    The sum of the adjacent angles formed by two intersecting lines is always 180° (linear pair).
  3. Find the value of xxx if two intersecting lines form the following two angles: 5x+20°5x + 20°5x+20° and 2x+50°2x + 50°2x+50°.
    Answer:
    Since the angles are vertically opposite, they are equal:

5x+20°=2x+50°5x + 20° = 2x + 50°5x+20°=2x+50°

Solving for xxx:5x−2x=50°−20°⇒3x=30°⇒x=10°5x – 2x = 50° – 20° \Rightarrow 3x = 30° \Rightarrow x = 10°5x−2x=50°−20°⇒3x=30°⇒x=10°

  1. What is the sum of the measures of the four angles formed by two intersecting lines?
    Answer:
    The sum of the measures of the four angles formed by two intersecting lines is 360°.

Section 4: Solving Problems Using Angle Properties

  1. In a triangle, if one angle is 50°, the second angle is 70°, find the third angle.
    Answer:
    The sum of the angles in a triangle is always 180°.
    The third angle is:

180°−50°−70°=60°180° – 50° – 70° = 60°180°−50°−70°=60°

  1. If the sum of two supplementary angles is 150°, and one angle is 20° more than the other, find the angles.
    Answer:
    Let the smaller angle be xxx.
    The larger angle is x+20°x + 20°x+20°.
    Since they are supplementary:

x+(x+20°)=150°⇒2x+20°=150°⇒2x=130°⇒x=65°x + (x + 20°) = 150° \Rightarrow 2x + 20° = 150° \Rightarrow 2x = 130° \Rightarrow x = 65°x+(x+20°)=150°⇒2x+20°=150°⇒2x=130°⇒x=65°

Therefore, the smaller angle is 65° and the larger angle is 65°+20°=85°65° + 20° = 85°65°+20°=85°.

  1. In a quadrilateral, if three of the angles are 90°, 110°, and 80°, find the fourth angle.
    Answer:
    The sum of the interior angles of a quadrilateral is 360°.
    Therefore, the fourth angle is:

360°−(90°+110°+80°)=360°−280°=80°360° – (90° + 110° + 80°) = 360° – 280° = 80°360°−(90°+110°+80°)=360°−280°=80°

  1. Find the value of xxx if the two angles are supplementary and one angle is 4x+20°4x + 20°4x+20° and the other is 5x−10°5x – 10°5x−10°.
    Answer:
    Since the angles are supplementary:

(4x+20°)+(5x−10°)=180°(4x + 20°) + (5x – 10°) = 180°(4x+20°)+(5x−10°)=180°

Simplifying:9x+10°=180°⇒9x=170°⇒x=170°9≈18.89°9x + 10° = 180° \Rightarrow 9x = 170° \Rightarrow x = \frac{170°}{9} \approx 18.89°9x+10°=180°⇒9x=170°⇒x=9170°​≈18.89°

  1. In a polygon with nnn sides, what is the measure of each exterior angle if the polygon is regular?
    Answer:
    The measure of each exterior angle of a regular polygon is:

360°n\frac{360°}{n}n360°​


These 20 additional questions provide a deeper understanding of angles, parallel lines, transversals, and intersecting lines. These problems range from basic to slightly more complex applications, reinforcing the core concepts of Chapter 6: Lines and Angles. Feel free to ask if you need further explanation on any of the solutions!

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